3x(x+2)=3(x^2-2)

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Solution for 3x(x+2)=3(x^2-2) equation: 


Simplifying
3x(x + 2) = 3(x2 + -2)

Reorder the terms:
3x(2 + x) = 3(x2 + -2)
(2 * 3x + x * 3x) = 3(x2 + -2)
(6x + 3x2) = 3(x2 + -2)

Reorder the terms:
6x + 3x2 = 3(-2 + x2)
6x + 3x2 = (-2 * 3 + x2 * 3)
6x + 3x2 = (-6 + 3x2)

Add '-3x2' to each side of the equation.
6x + 3x2 + -3x2 = -6 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
6x + 0 = -6 + 3x2 + -3x2
6x = -6 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
6x = -6 + 0
6x = -6

Solving
6x = -6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = -1

Simplifying
x = -1

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